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15p^2+8p^2-60p=p
We move all terms to the left:
15p^2+8p^2-60p-(p)=0
We add all the numbers together, and all the variables
23p^2-61p=0
a = 23; b = -61; c = 0;
Δ = b2-4ac
Δ = -612-4·23·0
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-61}{2*23}=\frac{0}{46} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+61}{2*23}=\frac{122}{46} =2+15/23 $
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